SAT Algebra Practice Questions

Algebra is the largest math domain on the digital SAT: roughly 13 to 15 of the 44 math questions, about 35% of your math score. It covers linear equations in one and two variables, systems of two linear equations, linear inequalities, and linear functions.

Most lost points here are not from hard concepts. They come from rushing the translation step (turning a word problem into an equation), sign slips when isolating a variable, and misreading which quantity a coefficient represents. The questions below are drawn from our bank of 4,100+ and mirror the real test's range: work each one before opening the explanation.

  1. Question 1Linear equations in one variable · easy

    H=2.403L+23.31H=2.403 L+23.31

    A group of biology students conducted an experiment to study the relationship between a person's femur length and the person's height. The given equation describes the relationship between the length LL, in inches, of a student's femur and the student's estimated height HH, in inches, for the students in the group. Which of the following is the best interpretation of 2.403 in this context?

    AThe increase in a student's estimated height, in inches, for each increase of 1 inch in the student's femur length.
    BThe increase in a student's femur length, in inches, for each increase of 1 inch in the student's estimated height.
    CThe increase in a student's femur length, in inches, for each increase of 23.31 inches in the student's estimated height.
    DThe estimated height, in inches, of a student whose femur has a length of LL inches.
    Show answer & explanation
    Correct answer: A

    The increase in a student's estimated height, in inches, for each increase of 1 inch in the student's femur length.

    Option A is correct

    1. The equation H=2.403L+23.31H = 2.403L + 23.31 has the form H=mL+bH = mL + b, so 2.403 is the slope: the change in HH produced by increasing LL by exactly 1.

    2. LL is femur length in inches and HH is estimated height in inches. So each additional inch of femur length adds 2.403 inches to the estimated height.

    3. Choice B reverses the relationship — that would describe the slope if the equation were solved for LL instead. Choice D describes what the whole expression 2.403L+23.312.403L + 23.31 computes, not what the single number 2.403 means.

    Answer: A.

  2. Question 2Systems of two linear equations in two variables · medium
    y<6x16y>4x9\begin{gathered} y<-6 x-16 \\ y>-4 x-9 \end{gathered}

    For which of the following tables are all the values of xx and their corresponding values of yy solutions to the given system of inequalities?

    Axy5962586\begin{array}{|c|c|} \hline x & y \\ \hline -5 & 9 \\ \hline -6 & 25 \\ \hline -8 & -6 \\\hline \end{array}
    Bxy510618830\begin{array}{|c|c|} \hline x & y \\ \hline -5 & 10 \\ \hline -6 & 18 \\ \hline -8 & 30 \\\hline \end{array}
    Cxy512620831\begin{array}{|c|c|} \hline x & y \\ \hline -5 & 12 \\ \hline -6 & 20 \\ \hline -8 & 31 \\\hline \end{array}
    Dxy513617825\begin{array}{|c|c|} \hline x & y \\ \hline -5 & 13 \\ \hline -6 & 17 \\ \hline -8 & 25 \\\hline \end{array}
    Show answer & explanation
    Correct answer: D

    Option D is correct

    1. A table works only if every row satisfies both inequalities, so test rows and eliminate on the first failure.

    2. All four tables use x=5,6,8x = -5, -6, -8. Compute both boundaries once: at x=5x=-5, 6x16=14-6x-16 = 14 and 4x9=11-4x-9 = 11, so yy must satisfy 11<y<1411 < y < 14. At x=6x=-6: 20 and 15, so 15<y<2015 < y < 20. At x=8x=-8: 32 and 23, so 23<y<3223 < y < 32.

    3. Choice A gives y=9y=9 at x=5x=-5, but 9<119 < 11 — fails. Choice B gives y=10y=10 — also below 11. Choice C gives y=20y=20 at x=6x=-6, but y<20y < 20 must be strict — fails.

    4. Choice D gives 13, 17, 25, which land inside (11,14)(11,14), (15,20)(15,20), and (23,32)(23,32) respectively.

    Answer: D.

  3. Question 3Linear inequalities in one or two variables · easy

    y>5x4y>5 x-4

    For which of the following tables are all the values of x and their corresponding values of yy solutions to the given inequality?

    Axy411621936\begin{array}{|c|c|} \hline x & y \\ \hline 4 & 11 \\ \hline 6 & 21 \\ \hline 9 & 36 \\\hline \end{array}
    Bxy416626941\begin{array}{|c|c|} \hline x & y \\ \hline 4 & 16 \\ \hline 6 & 26 \\ \hline 9 & 41 \\\hline \end{array}
    Cxy421631946\begin{array}{|c|c|} \hline x & y \\ \hline 4 & 21 \\ \hline 6 & 31 \\ \hline 9 & 46 \\\hline \end{array}
    Dxy421621941\begin{array}{|c|c|} \hline x & y \\ \hline 4 & 21 \\ \hline 6 & 21 \\ \hline 9 & 41 \\\hline \end{array}
    Show answer & explanation
    Correct answer: C

    Option C is correct

    1. For each xx in the tables, compute the boundary 5x45x - 4; a valid row needs yy strictly greater than it.

    2. At x=4x = 4: 5(4)4=165(4)-4 = 16. At x=6x = 6: 26. At x=9x = 9: 41.

    3. Choice A starts with y=11y = 11 at x=4x=4, and 11<1611 < 16 — fails immediately. Choice B gives y=16y = 16 at x=4x=4, but the inequality is strict, so y=16y = 16 is on the line, not above it — fails. Choice D gives y=21y = 21 at x=6x = 6, but 21<2621 < 26 — fails.

    4. Choice C gives 21>1621 > 16, 31>2631 > 26, and 46>4146 > 41: every row clears its boundary.

    Answer: C.

  4. Question 4Linear Functions · hard

    A polygonal chain is a connected series of line segments whose length is defined as the sum of the lengths of the line segments it is made of. A polygonal chain with a length of 33 centimeters (cm) is extended by adding line segments that each have a length of 8r8 - r cm. Which function ff represents the total length, in cm, of the extended polygonal chain after xx line segments are added?

    Af(x)=33(8r)+xf(x) = 33(8 - r) + x
    Bf(x)=8xrx+33f(x) = 8x - rx + 33
    Cf(x)=8xr+33f(x) = 8x - r + 33
    Df(x)=(41r)xf(x) = (41 - r)x
    Show answer & explanation
    Correct answer: B

    f(x)=8xrx+33f(x) = 8x - rx + 33

    Option B is correct

    1. The chain starts at 33 cm, and that fixed starting length does not change as segments are added — it is the constant term.

    2. Each added segment contributes (8r)(8 - r) cm, so adding xx segments contributes (8r)x(8-r)x cm in total.

    3. Total length: f(x)=33+(8r)xf(x) = 33 + (8 - r)x. Distribute: f(x)=8xrx+33f(x) = 8x - rx + 33.

    4. Choice A multiplies the starting length by (8r)(8-r), which wrongly rescales the original chain. Choice C forgets to multiply rr by xx, subtracting rr only once no matter how many segments are added.

    Answer: B.

  5. Question 5Linear equations in one variable · medium

    In one week in 2017, a technician earned a total of $700 by working at her regular job and at a second job doing part-time work. The equation 16h+13c=70016 h+13 c=700 represents this situation, where hh is the number of hours worked at her regular job and cc is the number of hours worked at her second job. Which of the following is the best interpretation of 16 in this context?

    AThe amount, in dollars, the technician earned for each hour she worked at her regular job
    BThe amount, in dollars, the technician earned for each hour she worked at her second job
    CThe number of hours the technician worked in one week at her regular job
    DThe number of hours the technician worked in one week at her second job
    Show answer & explanation
    Correct answer: A

    The amount, in dollars, the technician earned for each hour she worked at her regular job

    Option A is correct

    1. In 16h+13c=70016h + 13c = 700, the term 16h16h must be an amount of money, because it adds with 13c13c to make 700$.

    2. Since hh counts hours at the regular job, multiplying it by 16 turns hours into dollars only if 16 is the pay rate, in dollars per hour, at the regular job.

    3. Choice B attaches the rate to the wrong job — the second job's rate is 13, the coefficient of cc. Choices C and D confuse a rate (a coefficient) with a quantity of hours (a variable): the number of hours worked is hh or cc, not 16.

    Answer: A.

  6. Question 6Systems of two linear equations in two variables · easy
    y>5x21y>3x8\begin{gathered} y>-5 x-21 \\ y>-3 x-8 \end{gathered}

    For which of the following tables are all the values of xx and their corresponding values of yy solutions to the given system of inequalities?

    A(8,14),(9,35),(11,3)(-8,14),(-9,35),(-11,3)
    B(8,19),(9,22),(11,3)(-8,19),(-9,22),(-11,-3)
    C(14,8),(35,9),(3,11)(14,-8),(35,-9),(3,-11)
    D(19,8),(22,9),(3,11)(19,-8),(22,-9),(-3,-11)
    Show answer & explanation
    Correct answer: C

    (14,8),(35,9),(3,11)(14,-8),(35,-9),(3,-11)

    Option C is correct

    1. Each option lists ordered pairs (x,y)(x, y) — and the trap here is that choices A and B use the same numbers as C and D with the coordinates swapped, so keep the order straight.

    2. Test choice C. For (14,8)(14, -8): 5(14)21=91-5(14)-21 = -91 and 3(14)8=50-3(14)-8 = -50; -8 is greater than both. For (35,9)(35, -9): boundaries -196 and -113; -9 beats both. For (3,11)(3, -11): boundaries -36 and -17; -11 beats both. Every pair works.

    3. Why the others fail: choice A's first pair (8,14)(-8, 14) gives 5(8)21=19-5(-8)-21 = 19, and 14>1914 > 19 is false. Choice B's first pair (8,19)(-8, 19) gives 19>1919 > 19, false because the inequality is strict. Choice D's pair (3,11)(-3, -11) gives 5(3)21=6-5(-3)-21 = -6, and 11>6-11 > -6 is false.

    Answer: C.

  7. Question 7Linear inequalities in one or two variables · easy

    y>72x+17y > -\frac{7}{2}x + 17

    For which of the following tables are all the values of xx and their corresponding values of yy solutions to the given inequality?

    Axy22621245\begin{array}{|c|c|} \hline x & y \\ \hline -2 & 26 \\ \hline 2 & 12 \\ \hline 4 & 5 \\\hline \end{array}
    Bxy2262845\begin{array}{|c|c|} \hline x & y \\ \hline -2 & 26 \\ \hline 2 & 8 \\ \hline 4 & 5 \\\hline \end{array}
    Cxy2222841\begin{array}{|c|c|} \hline x & y \\ \hline -2 & 22 \\ \hline 2 & 8 \\ \hline 4 & 1 \\\hline \end{array}
    Dxy22421245\begin{array}{|c|c|} \hline x & y \\ \hline -2 & 24 \\ \hline 2 & 12 \\ \hline 4 & 5 \\\hline \end{array}
    Show answer & explanation
    Correct answer: A

    Option A is correct

    1. Compute the boundary 72x+17-\tfrac{7}{2}x + 17 for the three xx-values every table uses.

    2. At x=2x = -2: 7+17=247 + 17 = 24. At x=2x = 2: 7+17=10-7 + 17 = 10. At x=4x = 4: 14+17=3-14 + 17 = 3.

    3. A valid table needs yy strictly above the boundary in every row. Choice B fails at x=2x=2 (8<108 < 10). Choice C fails at x=2x=-2 (22<2422 < 24). Choice D fails at x=2x=-2: y=24y = 24 equals the boundary, and equality is not allowed by a strict inequality.

    4. Choice A gives 26>2426 > 24, 12>1012 > 10, and 5>35 > 3 — all three rows clear.

    Answer: A.

  8. Question 8Linear Functions · easy

    A linear function ff gives a company’s profit, in dollars, for selling xx items. The company’s profit is $190 when it sells 4 items, and its profit is $670 when it sells 10 items. Which equation defines ff?

    Af(x)=180x670f(x) = 180x - 670
    Bf(x)=67xf(x) = 67x
    Cf(x)=80x10xf(x) = 80x - 10x
    Df(x)=80x130f(x) = 80x - 130
    Show answer & explanation
    Correct answer: D

    f(x)=80x130f(x) = 80x - 130

    Option D is correct

    1. A linear function through the points (4,190)(4, 190) and (10,670)(10, 670) has slope 670190104=4806=80\dfrac{670 - 190}{10 - 4} = \dfrac{480}{6} = 80 — the company earns 80$ more per extra item.

    2. Write f(x)=80x+bf(x) = 80x + b and substitute (4,190)(4, 190): 190=320+b190 = 320 + b, so b=130b = -130.

    3. So f(x)=80x130f(x) = 80x - 130. Check with the second point: 80(10)130=67080(10) - 130 = 670. ✓

    4. Choice C looks plausible but simplifies to 70x70x, which gives f(4)=280f(4) = 280, not 190. Choice B forces the line through the origin, which contradicts both given points.

    Answer: D.

  9. Question 9Systems of two linear equations in two variables · medium

    A biologist is designing a study to observe the behavior of male and female amethyst-throated hummingbirds. According to the study's design, at least 91 hummingbirds will be observed, and the positive difference between the number of males, xx, and the number of females, yy, will not exceed 8. Which of the following systems of inequalities represents this situation?

    Ax+y91x+y \geq 91 xy8|x-y| \leq 8
    Bx+y91x+y \geq 91 xy8x-y \leq 8
    Cx+y91x+y \leq 91 xy8x-y \leq 8
    Dx+y<91x+y < 91 xy<8|x-y| < 8
    Show answer & explanation
    Correct answer: A

    x+y91x+y \geq 91 xy8|x-y| \leq 8

    Option A is correct

    1. "At least 91 hummingbirds will be observed" means the total is 91 or more: x+y91x + y \geq 91. That eliminates choices C and D, which cap the total instead.

    2. "The positive difference between the number of males and females will not exceed 8" must hold whichever group is larger. If females outnumber males, xyx - y is negative and choice B's xy8x - y \leq 8 would be satisfied even with a difference of 50.

    3. The absolute value captures both directions: xy8|x - y| \leq 8 says the gap is at most 8 regardless of which count is bigger.

    Answer: A.

  10. Question 10Linear Functions · medium

    A landscaping company mixes oil with gasoline to power its tools. A chainsaw requires 8 ounces of oil per gallon of gasoline. A lawnmower requires 4 ounces of oil per gallon of gasoline. The company uses a total of 21 ounces of oil in its mixes for the chainsaw and lawnmower. Which of the following equations represents this situation, where xx represents the amount of gasoline, in gallons, in the mix for the chainsaw and yy represents the amount of gasoline, in gallons, in the mix for the lawnmower?

    A2(x+2y)=212(x + 2y) = 21
    B2(2x+y)=212(2x + y) = 21
    C4(x+2y)=214(x + 2y) = 21
    D4(2x+y)=214(2x + y) = 21
    Show answer & explanation
    Correct answer: D

    4(2x+y)=214(2x + y) = 21

    Option D is correct

    1. Translate each mix into ounces of oil. The chainsaw uses 8 ounces per gallon and gets xx gallons: 8x8x ounces. The lawnmower uses 4 ounces per gallon and gets yy gallons: 4y4y ounces.

    2. The total oil used is 21 ounces: 8x+4y=218x + 4y = 21.

    3. No choice is written in that form, so factor. The greatest common factor of 8 and 4 is 4: 8x+4y=4(2x+y)8x + 4y = 4(2x + y), giving 4(2x+y)=214(2x + y) = 21.

    4. Expanding the wrong choices exposes them: choice A is 2x+4y=212x + 4y = 21 and choice C is 4x+8y=214x + 8y = 21 — both attach the oil rates to the wrong tools.

    Answer: D.

Want the other 4,090+ questions?

These 10 questions are a public sample. BrightSAT has 4,100+ digital SAT questions across every domain and skill, plus Bluebook-style full-length adaptive practice tests, targeted practice, and score reports that show exactly where you lose points.

Start practicing free